Problem-Solving and Data Analysis is the domain where the least arithmetic is required and the most marks are lost, because two of the ideas in it are examined regularly and taught almost never: what a margin of error permits, and why an observed difference is not a cause. This material gives each of them a question of its own, and builds the other ten around the statistics that surround them.
Three are about the center of a set. A median of eight sunflower heights where one plant is twice the size of any other. A week of temperatures where a single reading of twenty-eight degrees drags the mean to seven while the median sits at four, so the question becomes which of the two describes the week. And a set of nine commuting times containing a ninety-six, where removing that one reading moves the mean by more than eight minutes and the median by half of one — which is the clearest way to see what each statistic is actually made of.
Two are probability read off counts stated in sentences rather than set in a table. One of them is conditional, and the explanation names the group the fraction is taken from, because taking it from the whole hundred rather than from the forty who prefer digital books is the single error this question type is built to catch.
Two concern a line fitted to data: what its slope means with units attached, what its intercept means, and what it predicts at a stated input — where forgetting to add the intercept is the standard slip.
Two ask what a sample supports. Five hundred students at one university tell you about that university; two hundred employees at one company give an estimate for that company. The wrong options each stretch the conclusion to a population nobody sampled, which is how a sound survey gets misreported.
The last two are the pair named at the start. A margin of error marks out a band around an estimate — thirty-eight percent plus or minus three points means thirty-five to forty-one — and it is not a chance of being wrong. And an observational study, however large its difference, cannot rule out the confounding variable that produced it, because nothing was assigned at random.
Every situation here was invented for the exercise, and nothing is reproduced from any published test.
Every data set here is small enough to hold in the head and is listed in words inside its own question; there are no tables and no graphs. Among them: eight sunflower heights of 120, 122, 125, 125, 128, 130, 135 and 250 centimeters; a week of temperatures at 2, 3, 3, 4, 5, 6 and 28 degrees; nine commuting times of 14, 15, 15, 17, 18, 20, 21, 22 and 96 minutes; a hundred library patrons of whom forty are students and forty prefer digital books; two hundred commuters, eighty of them on the train; the fitted lines $y = 50x + 100$ for repair costs and $y = 2.5x + 10$ for a seedling's height; five hundred students surveyed at one university; two hundred employees of five thousand; a county bus survey reporting thirty-eight percent plus or minus three points; and an observational study of tablets and test scores. Zestly is an independent study tool. It is not affiliated with the College Board, which owns the PSAT/NMSQT, and it is not an exam centre.
A local garden club measured the heights of eight sunflowers in centimeters: 120, 122, 125, 125, 128, 130, 135, and 250. What is the median height of these sunflowers?
126.5
To find the median of an even-numbered set, take the average of the two middle values. The ordered set is 120, 122, 125, 125, 128, 130, 135, 250. The middle values are 125 and 128. The calculation is $\frac{125 + 128}{2} = 126.5$.
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