National 5 Mathematics: expressions and formulae

Expressions and formulae is the algebra half of National 5 Maths, and most of it is sat without a calculator — so the marks turn on whether the manipulation is automatic. This set drills the ten things that come up over and over: simplifying a surd, the index laws, a fractional index, expanding a pair of brackets, factorising a trinomial and a difference of two squares, cancelling an algebraic fraction, changing the subject of a formula, rounding to significant figures, and substituting a negative value.

Every wrong option is a slip candidates actually make rather than a random number — a sign lost when the middle terms are collected, the root and the power applied in the wrong order, decimal places counted instead of significant figures, a negative squared and left negative. The explanations show the working line by line and name which specific mistake produces the closest wrong answer, so a wrong click tells you what went wrong and not just that something did.

Zestly is an independent study tool. It is not affiliated with any exam board and it is not an exam centre.

  • Simplify a surd by pulling out the largest square factor
  • Apply the index laws for multiplying, dividing and raising a power to a power
  • Evaluate a fractional index by taking the root first and then the power
  • Expand a pair of brackets and collect the middle terms without losing a sign
  • Factorise a trinomial and recognise a difference of two squares
  • Simplify an algebraic fraction by factorising and cancelling
  • Change the subject of a formula using inverse operations in the right order
  • Round to significant figures, counting from the first non-zero digit
  • Substitute negative values correctly, keeping a squared negative positive

Evaluate $8^{\frac{2}{3}}$ as a whole number. — The denominator 3 is the root and the numerator 2 is the power, so $8^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 2^2 = 4$.

Sample question

Express $\sqrt{72}$ in its simplest surd form.

See the answer

$6\sqrt{2}$

To simplify $\sqrt{72}$, find the largest square factor: $\sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6\sqrt{2}$. Choosing $4\sqrt{3}$ is a common error resulting from $\sqrt{16 \times 3}$, which equals $\sqrt{48}$.

Try this quiz →Try this exam →Practice these flashcards →Try this written work →

← National 5 Mathematics

↑ National 5 and Higher (Scotland)