Higher trigonometry asks for a set of formulae to be available instantly and applied without sign errors: the compound angle expansions, the double angle formulae, the Pythagorean identity, and the wave function that rewrites a sum of a sine and a cosine as a single shifted cosine.
Ten single-answer questions cover converting degrees to radians, the exact value of a standard angle, the expansion of sin(A + B), finding a double angle from a known sine, simplifying an expression with the Pythagorean identity, solving a cosine equation that has two solutions in the range, expressing as a single wave, the maximum and minimum of a transformed sine graph, building the exact value of cos 75 degrees out of 45 and 30, and reading the period off a cosine graph.
The wrong options are the errors that actually appear: the sine and cosine compound formulae swapped, the factor of two dropped from a double angle, the amplitude found by adding the coefficients rather than by Pythagoras, the auxiliary angle taken from the wrong ratio, and the amplitude mistaken for the maximum of a graph that has been shifted vertically.
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Express $3\cos x^\circ + 4\sin x^\circ$ in the form $k\cos(x - a)^\circ$. — Here $k = \sqrt{3^2 + 4^2} = 5$, and equating coefficients gives $k\cos a = 3$ and $k\sin a = 4$, so $\tan a = \frac{4}{3}$ and $a \approx 53.1^\circ$.
Given that $\sin x = \frac{3}{5}$ and $x$ is an acute angle, what is the exact value of $\sin 2x$?
$\frac{24}{25}$
Using the double angle formula $\sin 2x = 2 \sin x \cos x$. Since $\sin x = \frac{3}{5}$ and $x$ is acute, $\cos x = \frac{4}{5}$ (from a 3, 4, 5 triangle). Thus, $\sin 2x = 2 \cdot \frac{3}{5} \cdot \frac{4}{5} = \frac{24}{25}$.
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