Magnetic fields and electromagnetic induction close the A2 fields sequence, and they carry some of the paper's most reliable calculation marks — provided the angles, signs and laws are kept straight. This quiz drills exactly those pressure points.
The magnetic-force questions apply both force laws with real values: F = BIl sin θ for a wire at 30° to the field (0.40 N — a calculation the automated verifier itself got wrong during checking, double-applying the sine; the key was confirmed by manual computation, which says something about how easy the slip is), and the qualitative physics of F = BQv — why the magnetic force on a moving proton does no work, changes no kinetic energy, and produces circular motion by acting as a centripetal force.
The induction questions build from definitions to dynamics: flux linkage for a 50-turn coil in a stated field, Faraday's law applied to a changing flux through 200 turns (16 V, worked in full), the EMF across a rod moving through a field (Blv), which changes genuinely induce an EMF at all, and Lenz's law traced to its foundation — conservation of energy. A generator question identifies every factor that raises peak EMF: frequency, flux density, turns.
The transformer questions complete the set: the turns-ratio relation worked as a statement selection on a 1000:200 step-down transformer, and an efficiency calculation recovering secondary current from input power and output voltage at 90% efficiency.
All values are supplied in the questions, consistent with the exam's data booklet, and each explanation names the law being invoked before substituting — the habit that keeps six-mark induction explanations coherent.
Topic scope follows section 3.7.5 (Magnetic fields) of the current A-level physics subject content: force on current-carrying conductors and moving charges, flux and flux linkage, electromagnetic induction, Faraday's and Lenz's laws, AC generators and transformers.
A straight wire of length 0.25 m carries a current of 4.0 A. It is placed at an angle of 30 degrees to a uniform magnetic field of flux density 0.80 T. Calculate the magnitude of the magnetic force acting on the wire.
0.40 N
The force on a current-carrying wire is given by $F = BIl \sin(\theta)$. Substituting the values: $F = 0.80 \cdot 4.0 \cdot 0.25 \cdot \sin(30^\circ) = 0.80 \cdot 4.0 \cdot 0.25 \cdot 0.5 = 0.40 \text{ N}$.