Redox chemistry runs from Year 1 oxidation states to Year 2 electrochemical cells, and this quiz covers the full arc.
The foundations are tested through the chlorine-in-alkali disproportionation (one element simultaneously oxidised to +1 and reduced to −1), oxidation state assignment in the dichromate ion (the 2x − 14 = −2 algebra giving +6), and the balanced half-equation for manganate(VII) reduction in acid — the 8H⁺, 5e⁻ workhorse of titration chemistry.
The electrochemistry questions build the full Year 2 apparatus. The standard hydrogen electrode is specified exactly: platinum electrode, hydrogen at 100 kPa, 1.0 mol dm⁻³ H⁺, defined as zero. Cell EMF is calculated twice — the iron/tin cell at +0.62 V and the aluminium/zinc cell at +0.90 V, the second requiring care with two negative electrode potentials. Feasibility prediction from the electrochemical series is tested through which metal/ion pairings give a positive cell EMF, and the series' logic — more positive means better oxidising agent — gets a dedicated question.
Practical electrochemistry completes the set: the alkaline hydrogen fuel cell with oxidation at the anode and reduction at the cathode, and the factors that shift a measured electrode potential away from its standard value (temperature and concentration — the Nernst territory A-level touches qualitatively).
Explanations always show the electron bookkeeping, which is the habit that makes redox reliable rather than memorised.
Aligned to the redox core of the DfE A level science subject content: oxidation states, half-equations, standard electrode potentials, cell EMF, feasibility and fuel cells.
Given the standard electrode potentials: E(Fe3+/Fe2+) = +0.77 V and E(Sn4+/Sn2+) = +0.15 V. What is the EMF of a cell constructed from these two half-cells?
+0.62 V
The cell EMF is calculated as E(cathode) - E(anode). To be spontaneous, the more positive potential acts as the cathode: 0.77 - 0.15 = +0.62 V.
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