Vectors at A-Level extend from 2D arithmetic into 3D geometry, and the exam questions turn on a handful of precise ideas: magnitude, scalar multiples, position versus displacement, and the section formula. This quiz covers them all with concrete components throughout.
The foundational questions handle magnitude in 3D — the 3-4-12 vector whose length is exactly 13, and the distance of a point from the origin as the magnitude of its position vector, given in exact form √56 = 2√14. The parallel-vector questions test the defining criterion, scalar multiplication, twice: identifying which vectors are multiples of 2i − 6j + 4k (including the negative multiple −1.5v, the case students most often miss), and a statement-checking question on −i + 2j − 2k where the vector is parallel to i − 2j + 2k precisely because it equals −1 times it, alongside the magnitude and unit vector.
The position-vector questions cover the operational core: the displacement AB as b − a, the resultant 2a − b with its sign trap in the subtracted component, midpoints and exact distances in 3D from points P(1,2,3) and Q(4,5,6), and collinearity through scalar-multiple criteria. The section formula appears in ratio form: the point dividing AB in ratio 1:3, computed from the weighted average.
Kinematics closes the set with the constant-velocity position update r = vt — the vector bridge into mechanics.
Explanations show component-by-component working, the format that earns method marks on the written paper.
Topic scope follows section J (Vectors) of the DfE's prescribed AS and A level mathematics subject content — 100% common across all exam boards: magnitude and direction, position vectors, 2D and (A level) 3D vectors, geometric problems, and applications to kinematics.
A point $M$ divides the line segment $AB$ in the ratio $1:3$. If $\mathbf{a} = 0$ and $\mathbf{b} = 4\mathbf{i} + 8\mathbf{j}$, what is the position vector of $M$?
$\mathbf{i} + 2\mathbf{j}$
The position vector of $M$ is $\frac{3\mathbf{a} + 1\mathbf{b}}{1+3} = \frac{0 + 4\mathbf{i} + 8\mathbf{j}}{4} = \mathbf{i} + 2\mathbf{j}$.
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